1836 United States presidential election in Louisiana
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| Elections in Louisiana |
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 Government |
The 1836 United States presidential election in Louisiana took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.
Louisiana voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Louisiana by a narrow margin of 3.48%.
Results
[edit]| 1836 United States presidential election in Louisiana[1] | |||||
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| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic | Martin Van Buren | 3,842 | 51.74% | 5 | |
| Whig | Hugh White | 3,583 | 48.26% | 0 | |
| Totals | 7,425 | 100.0% | 5 | ||
See also
[edit]References
[edit]- ^ "1836 Presidential General Election Results - Louisiana". U.S. Election Atlas. Retrieved August 4, 2012.
State and district results of the 1836 United States presidential election | ||
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